Given a binary array, find the maximum number of consecutive 1s in this array.

Example 1:

Input: [1,1,0,1,1,1]Output: 3Explanation: The first two digits or the last three digits are consecutive 1s.    The maximum number of consecutive 1s is 3.

Note:

• The input array will only contain 0 and 1.
• The length of input array is a positive integer and will not exceed 10,000

题目要求连续1的个数。遍历数组进行判断取最大的连续1的个数即可。

class Solution {public:    int findMaxConsecutiveOnes(vector
     
      & nums) {        int res = 0, cnt = 0;        for (int i = 0; i != nums.size(); i++) {            if (nums[i] == 1)                 cnt++;            else                cnt = 0;            res = max(res, cnt);        }        return res;    }};// 36 ms